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When two inductors $L_1$ and $L_2$ are connected in **series** (no mutual inductance), the equivalent inductance is:
A$L_1 + L_2$
B$L_1 L_2/(L_1 + L_2)$
C$1/L_1 + 1/L_2$
D$\sqrt{L_1 L_2}$
Answer & Solution
Correct answer: A. $L_1 + L_2$
Inductors in series add directly: $L_{eq} = L_1 + L_2$ (analogous to resistors in series). Parallel combination uses the reciprocal sum.
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