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The largest number that divides 280 and 1245 leaving remainders 4 and 3 respectively is
A46
B138
C276
D28
Answer & Solution
Correct answer: B. 138
280 - 4 = 276; 1245 - 3 = 1242. Required = HCF(276, 1242). 1242 = 4 x 276 + 138. HCF(276, 138) = 138. So 138.
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