For a 3 kg block connected over a frictionless pulley to a 20 kg trolley (μk = 0.04, g = 10 m s⁻²), the tension in the connecting string is:
A8.0 N
B22.0 N
C27.1 N
D30.0 N
Answer & Solution
Correct answer: C. 27.1 N
Using a = 0.96 m s⁻² from the system equations, T = 3(g − a) = 3(10 − 0.96) = 27.1 N (equivalently T = 8 + 20a).
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