A 0.15 kg ball moving at 12 m s⁻¹ is hit straight back along its path with the same speed. The magnitude of the impulse on the ball is:
A1.8 N s
B0 N s
C3.6 N s
D5.4 N s
Answer & Solution
Correct answer: C. 3.6 N s
Impulse = Δp = m(v_f − v_i) = 0.15[12 − (−12)] = 0.15×24 = 3.6 N s.
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