A 0.5 kg stone tied to a string is whirled in a horizontal circle of radius 2 m at a speed of 4 m s⁻¹. The tension in the string is:
A4 N
B1 N
C8 N
D2 N
Answer & Solution
Correct answer: A. 4 N
Tension supplies the centripetal force: T = mv²/R = 0.5×4²/2 = 4 N.
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