A circular field of radius 56 m has a path of width 7 m running around it. The area of the path is
- 3000 sq m
- 2200 sq m
- 2618 sq m
- 1500 sq m
Show answer and solution
Correct answer: C. 2618 sq m
1. Outer radius = 56 + 7 = 63 m; outer area = (22/7) × 63 × 63 = 12474 sq m.
2. Inner area = (22/7) × 56 × 56 = 9856 sq m.
3. Path area = 12474 - 9856 = 2618 sq m.
_Source: syllabus Mathematics, Ch 11 "Areas Related to Circles", §11.2_