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A cylindrical glass tube of radius 1 cm is filled with water to depth 14 cm. A sphere of radius 1 cm is dropped in. The new water level rises by

A2 cm
B2/3 cm
C1 cm
D4/3 cm
Answer & Solution
Correct answer: D. 4/3 cm
1. Sphere volume = (4/3) × pi × 1 cubed = (4/3) pi cu cm. 2. Cross-section = pi × 1 squared = pi. 3. Rise = (4/3) pi / pi = 4/3 cm. _Source: syllabus Mathematics, Ch 12 "Surface Areas and Volumes", §12.3_
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