alleryA spherical ball of iron of radius 6 cm is dropped into a cylinder of radius 12 cm partially full of water. The rise in water level is
A6 cm
B4 cm
C2 cm
D1 cm
Answer & Solution
Correct answer: C. 2 cm
1. Ball volume = (4/3) × pi × 216 = 288 pi cu cm; cylinder cross-section = pi × 144.
2. Rise = 288 pi / 144 pi = 2.
3. Rise = 2 cm.
_Source: syllabus Mathematics, Ch 12 "Surface Areas and Volumes", §12.3_
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