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A solid cylinder of radius r and height h is melted into a solid cone of the same radius r. The height of the cone is

Ah
B3 h
Ch/3
Dh/2
Answer & Solution
Correct answer: B. 3 h
1. Volume preserved: pi r squared h = (1/3) pi r squared H. 2. Solve for H: H = 3 h. 3. Hence 3 h. _Source: syllabus Mathematics, Ch 12 "Surface Areas and Volumes", §12.3_
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