PUCET (Punjab) Definite Integration — practice questions
29 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice PUCET (Punjab) Definite Integration in the app →The value of $\int_a^a f(x)\,dx$ is:For a definite integral with limits swapped, which identity holds?The **Fundamental Theorem** of integral calculus states that if $g(x)$ is an antiderivative of a continuous $fFor $a < c < b$, the integral $\int_a^b f(x)\,dx$ equals:If $f(x)$ is an **odd** function, then $\int_{-a}^{a} f(x)\,dx$ equals:If $f(x)$ is an **even** function, then $\int_{-a}^{a} f(x)\,dx$ equals:The 'King's property' of definite integration is:$\int_1^3 x\,dx$ equals:$\int_0^1 \dfrac{dx}{1+x^2}$ equals:$\int_{-\pi/2}^{\pi/2} in^3 x\,dx$ equals:$\int_{\pi/6}^{\pi/3} \cos x\,dx$ equals:$\int_{-1}^{5}(2x+3)\,dx$ equals:$\int_0^2 x^2\,dx$ equals:$\int_{-1}^{1} \dfrac{x^2}{1+x^2}\,dx$ equals:$\int_0^{\pi/2} \cos^3 x\,dx$ equals:$\int_0^{\pi/2} in x\,dx$ equals:Using the King's property, $\int_0^a f(x)\,dx$ equals:$\int_0^{\pi/2} in^2 x\,dx$ equals:If $f(x) = x^3 in^4 x$, then $\int_{-\pi/4}^{\pi/4} f(x)\,dx$ equals:$\int_{-2}^{2} (x^3 + x^2)\,dx$ equals:$\int_0^1 e^x\,dx$ equals:$\int_0^4 (x - x^2)\,dx$ equals:Evaluate $\int_2^3 7^x\,dx$:$\int_{-1}^{1} |5x - 3|\,dx$ equals:$\int_1^2 \dfrac{\log x}{x^2}\,dx$ equals:Using the King's property, evaluate $\int_0^{\pi/2} \dfrac{dx}{1 + qrt[3]{\tan x}}$:$\int_0^{\pi/2} qrt{1 - \cos 4x}\,dx$ equals:$\int_0^{\pi/2} \cos^2 x\,dx$ equals:Using definite integration as the limit of a sum, $\int_1^2 (2x + 5)\,dx$ equals: