Using definite integration as the limit of a sum, $\int_1^2 (2x + 5)\,dx$ equals:
A$6$
B$8$
C$10$
D$12$
Answer & Solution
Correct answer: B. $8$
**Direct evaluation:** $[x^2 + 5x]_1^2 = (4 + 10) - (1 + 5) = 14 - 6 = 8$.
(The limit-of-sum approach in the textbook yields the same: $\lim_n h\sum(7 + 2rh) = 7(1) + (1)(1+0) = 8$.)
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