$\int_0^4 (x - x^2)\,dx$ equals:
A$-40/3$
B$8$
C$40/3$
D$-8$
Answer & Solution
Correct answer: A. $-40/3$
**Antiderivative:** $x^2/2 - x^3/3$.
**Evaluate:** $[x^2/2 - x^3/3]_0^4 = (16/2 - 64/3) - 0 = 8 - 64/3 = (24-64)/3 = -40/3$.
Keep practising Unit 6B: Definite Integration & Riemann Sums
Browse all Unit 6B: Definite Integration & Riemann Sums questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
∫ from 0 to π/2 sin x cos x dx =For ∫ dx / sqrt(a² - x²), let x = a sin θ. Result:∫ from 0 to 2 (x² - 2x) dx =Reduction formula example: ∫ sinⁿ x dx (for n ≥ 2) =∫ from 1 to e (1/x) dx =∫ x ln x dx (integration by parts: u = ln x, dv = x dx):∫ from 0 to ∞ e^(-x) dx =Area under y = x² from x = 0 to x = 2: