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$\int_{-1}^{5}(2x+3)\,dx$ equals:

A24
B32
C42
D48
Answer & Solution
Correct answer: C. 42
**Antiderivative:** $x^2 + 3x$. **Evaluate:** $[x^2+3x]_{-1}^{5} = (25 + 15) - (1 - 3) = 40 - (-2) = 42$.
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