Start learning →

NEET UG Thermal Properties of Matter & Thermodynamics — practice questions — page 4

Explore 134 free Thermal Properties of Matter & Thermodynamics questions in NEET UG Physics. Open each question or exercise to read its content, reference answers and available explanation.

Practise Thermal Properties of Matter & Thermodynamics with Quill →

Thermal Properties of Matter & Thermodynamics questions and exercises with answers

Showing questions 91–120 of 134.

For an ideal gas, Cp - Cv equalsRead the answer and worked solution →An ideal gas has Cv = 20.8 J mol^-1 K^-1. Taking R = 8.31 J mol^-1 K^-1, Cp is aboutRead the answer and worked solution →For an ideal gas, Cv equals change in internal energy per kelvin per mole because U depends only onRead the answer and worked solution →A relation connecting state variables such as PV = µRT is calledRead the answer and worked solution →How many independent state variables does a fixed amount of ideal gas have?Read the answer and worked solution →A pressure-volume curve drawn at fixed temperature is calledRead the answer and worked solution →A gas in equilibrium is split into two equal halves. Which quantity is halved in each part?Read the answer and worked solution →Why can a gas during sudden free expansion into vacuum not be described by state variables?Read the answer and worked solution →A quasi-static process is one that isRead the answer and worked solution →In a quasi-static process, the system and surroundings differ in pressure byRead the answer and worked solution →A process in which the volume is kept constant is calledRead the answer and worked solution →An ideal gas expands isothermally and absorbs 600 J of heat. The work done by the gas isRead the answer and worked solution →During isothermal compression of an ideal gas, the gasRead the answer and worked solution →For an adiabatic change of an ideal gas, which quantity stays constant?Read the answer and worked solution →In the adiabatic relation PV^γ = constant, γ stands forRead the answer and worked solution →An insulated gas does 150 J of work on a piston. The change in its internal energy isRead the answer and worked solution →One mole of ideal gas with γ = 1.4 cools by 20 K in adiabatic expansion. With R = 8.3 J mol^-1 K^-1, the work done isRead the answer and worked solution →A gas in a rigid sealed tank absorbs 250 J of heat. The work done by the gas isRead the answer and worked solution →In an isobaric process of an ideal gas, the heat absorbed goes intoRead the answer and worked solution →A gas completes a cycle and absorbs a net 80 J of heat. The net work done by it isRead the answer and worked solution →'No process can have the sole result of turning heat from a reservoir fully into work' is theRead the answer and worked solution →The Clausius statement rules out a process whose only result isRead the answer and worked solution →By the second law, the coefficient of performance of a refrigerator can never beRead the answer and worked solution →The second law of thermodynamics says the efficiency of a heat engine can never beRead the answer and worked solution →Most spontaneous processes in nature areRead the answer and worked solution →Which is a main cause of irreversibility in real processes?Read the answer and worked solution →Which of these processes is reversible?Read the answer and worked solution →The French engineer who first studied the maximum efficiency of a heat engine in 1824 wasRead the answer and worked solution →The Carnot cycle consists ofRead the answer and worked solution →A Carnot engine has its source at 127 °C and sink at 27 °C. Its efficiency isRead the answer and worked solution →

Worked practice questions

For an ideal gas, Cp - Cv equals

  1. 3R
  2. R
  3. Cp/Cv
  4. γ
Show answer and solution

Correct answer: B. R

Mayer's relation for an ideal gas gives Cp - Cv = R, the universal gas constant.

Open this question →

An ideal gas has Cv = 20.8 J mol^-1 K^-1. Taking R = 8.31 J mol^-1 K^-1, Cp is about

  1. 20.8 J mol^-1 K^-1
  2. 29.1 J mol^-1 K^-1
  3. 12.5 J mol^-1 K^-1
  4. 37.4 J mol^-1 K^-1
Show answer and solution

Correct answer: B. 29.1 J mol^-1 K^-1

Cp = Cv + R = 20.8 + 8.31, which is about 29.1 J mol^-1 K^-1.

Open this question →

For an ideal gas, Cv equals change in internal energy per kelvin per mole because U depends only on

  1. density
  2. pressure
  3. volume
  4. temperature
Show answer and solution

Correct answer: D. temperature

At constant volume no work is done, and since U of an ideal gas depends only on temperature, Cv is simply dU/dT.

Open this question →

How to practise

  1. Choose a Thermal Properties of Matter & Thermodynamics question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

Put it into practice

Continue with Thermal Properties of Matter & Thermodynamics practice for NEET UG. Read explanations as you go. No signup form needed to start.

Practise Thermal Properties of Matter & Thermodynamics →

More Physics topics