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NEET UG Laws of Motion — practice questions — page 3

Explore 117 free Laws of Motion questions in NEET UG Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Laws of Motion questions and exercises with answers

Showing questions 61–90 of 117.

Momentum p of a body of mass m moving with velocity v is defined as:Read the answer and worked solution →A batsman hits a 0.15 kg ball back along the line of approach without changing its speed of 12 m s⁻¹. The magnitude of the impulse imparted to the ball is:Read the answer and worked solution →Newton's second law is often written as F = m a. This form is strictly valid when:Read the answer and worked solution →A force F acts on a particle making an angle θ with its instantaneous velocity. The component of velocity perpendicular to F:Read the answer and worked solution →A car of mass 1000 kg accelerates from rest to 20 m s⁻¹ in 5 s on a level road. The net horizontal force on the car is:Read the answer and worked solution →A stone of mass 0.5 kg is whirled in a horizontal circle of radius 1 m at constant angular speed 4 rad s⁻¹ by a string. The tension in the string is:Read the answer and worked solution →A constant force of 6 N acts for 4 s on a 2 kg body initially at rest. The kinetic energy of the body at the end of 4 s is:Read the answer and worked solution →True or false: what Aristotle got wrongRead the answer and worked solution →Complete Newton's first lawRead the answer and worked solution →Which law is this?Read the answer and worked solution →MomentumRead the answer and worked solution →True or false: inertia and forceRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Tap every statement the first law licensesRead the answer and worked solution →Flip and pair: name with contributionRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Order the historical argumentRead the answer and worked solution →Aristotle held that keeping a body moving needs something:Read the answer and worked solution →Aristotle explained a flying arrow by saying it is pushed by:Read the answer and worked solution →The Aristotelian law of motion is now regarded as:Read the answer and worked solution →The correct answer to the puzzle of motion came from:Read the answer and worked solution →Galileo's answer became the foundation of mechanics that is:Read the answer and worked solution →Galileo's revolutionary ideas dethroned the mechanics of:Read the answer and worked solution →Galileo's reasoning about motion led him to the law of:Read the answer and worked solution →By the first law, zero net external force means acceleration is:Read the answer and worked solution →Acceleration can be non zero only if there is a net external:Read the answer and worked solution →A spaceship far from everything with rockets off has net force:Read the answer and worked solution →That spaceship, if already moving, continues with velocity that is:Read the answer and worked solution →

Worked practice questions

Momentum p of a body of mass m moving with velocity v is defined as:

  1. p = m v
  2. p = ½ m v²
  3. p = m / v
  4. p = m v²
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Correct answer: A. p = m v

1. Momentum is a vector quantity equal to the product of mass and velocity. 2. p = m v, with direction the same as v. 3. Kinetic energy ½mv² is a scalar and not momentum. _Source: syllabus Physics Ch 4 "Laws of Motion", §4.5 Momentum, p. 53 Eq. (4.1)_

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A batsman hits a 0.15 kg ball back along the line of approach without changing its speed of 12 m s⁻¹. The magnitude of the impulse imparted to the ball is:

  1. 1.8 N s
  2. 2.4 N s
  3. 3.6 N s
  4. 4.8 N s
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Correct answer: C. 3.6 N s

1. The ball's velocity reverses, so Δv = 12 − (−12) = 24 m s⁻¹ in magnitude. 2. Impulse J = m Δv = 0.15 × 24 = 3.6 N s. 3. Forgetting the sign flip gives 0.15 × 12 = 1.8 N s — the common trap. _Source: syllabus Physics Ch 4 "Laws of Motion", Example 4.4, p. 56_

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Newton's second law is often written as F = m a. This form is strictly valid when:

  1. The body is moving at relativistic speeds
  2. The mass of the body is constant
  3. Friction is the only external force
  4. The force is impulsive in nature
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Correct answer: B. The mass of the body is constant

1. The general form is F = dp/dt where p = m v. 2. Expanding: dp/dt = m (dv/dt) + v (dm/dt). 3. The familiar form F = m a follows only when dm/dt = 0, i.e. mass is constant. 4. Variable-mass systems (rockets) need the full F = dp/dt form. _Source: syllabus Physics Ch 4 "Laws of Motion", §4.5 Eq. (4.3)–(4.5), p. 54_

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