What is the internal energy of 2 mol of helium at 300 K? (R = 8.31 J/mol K)
- 7.5 kJ
- 3.7 kJ
- 12.5 kJ
- 5.0 kJ
Show answer and solution
Correct answer: A. 7.5 kJ
U = n (3/2) R T = 2 × 1.5 × 8.31 × 300, about 7.5 kJ.
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Correct answer: A. 7.5 kJ
Correct answer: D. Its volume change is negligible
Correct answer: A. Average distance between two collisions
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