For rate = k[A][B]², the overall order is:

To determine the overall order of a chemical reaction from its rate law, we must sum the exponents of all the concentration terms. 1. **Identify the individual orders**: The given rate law is $\text{Rate} = k[A][B]^2$. - The exponent for $[A]$ is not written, which means it is $1$. So, the order with respect to $A$ is $1$. - The exponent for $[B]$ is $2$. So, the order with respect to $B$ is $2$. 2. **Sum the exponents**: $$\text{Overall Order} = \text{Order of } A + \text{Order of } B$$ $$\text{Overall Order} = 1 + 2 = 3$$ Therefore, the overall reaction order is $3$.