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MHT-CET Rotational Dynamics — practice questions — page 2

Explore 64 free Rotational Dynamics questions in MHT-CET Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Rotational Dynamics questions and exercises with answers

Showing questions 31–60 of 64.

For a smooth banked road of radius r and banking angle θ, the ideal speed v satisfiesRead the answer and worked solution →A smooth banked curve has radius 40 m and is designed for 20 m/s. What is the banking angle? (g = 10 m/s²)Read the answer and worked solution →On a banked road, the outer edge is raised so thatRead the answer and worked solution →A conical pendulum bob moves in aRead the answer and worked solution →A conical pendulum has string length L and semi-vertical angle θ. The radius of the circular path isRead the answer and worked solution →In a conical pendulum, the vertical component of tension balances the weight, soRead the answer and worked solution →Which gives the period of a conical pendulum of length L, angle θ with the vertical?Read the answer and worked solution →If the semi-vertical angle of a conical pendulum increases at fixed length, its periodRead the answer and worked solution →For a mass on a string in a vertical circle, the minimum speed at the top for the string to stay taut isRead the answer and worked solution →At the uppermost point of a vertical circle on a string, both weight and tension actRead the answer and worked solution →For a mass in a vertical circle, the difference between tensions at the lowest and highest points isRead the answer and worked solution →A mass swings in a vertical circle on a string. While going up, its speedRead the answer and worked solution →In the sphere of death, the force replacing tension in vertical circle dynamics isRead the answer and worked solution →For a vehicle on the top of a convex bridge, the centripetal equation isRead the answer and worked solution →A car on a convex bridge of radius 40 m loses contact with the road at what speed? (g = 10 m/s²)Read the answer and worked solution →A rider on the vertical wall of a cylindrical well stays up because friction balancesRead the answer and worked solution →A rider circles inside a cylindrical well of radius r with friction coefficient μ. Minimum speed to stay up isRead the answer and worked solution →The total kinetic energy of a rolling body of mass M, speed v, radius R and radius of gyration K isRead the answer and worked solution →In pure rolling, the centre of mass performsRead the answer and worked solution →Total kinetic energy of rolling comes fromRead the answer and worked solution →What fraction of the total kinetic energy of a rolling uniform disc is rotational?Read the answer and worked solution →For a rolling thin ring, translational and rotational kinetic energies are in the ratioRead the answer and worked solution →A solid cylinder rolls from rest down an incline through vertical height h. Its speed at the bottom isRead the answer and worked solution →Which of these reaches the bottom of an incline first when all roll from rest?Read the answer and worked solution →Moment of inertia of an object depends on its mass andRead the answer and worked solution →When mass distribution of a body is not mathematically integrable, its moment of inertia is foundRead the answer and worked solution →Two particles of 2 kg at 1 m and 3 kg at 2 m from an axis. Their moment of inertia in kg m² isRead the answer and worked solution →A body with I = 2 kg m² spins at 10 rad/s. Its rotational kinetic energy in joules isRead the answer and worked solution →A wheel has I = 0.5 kg m² and spins at 4 rad/s. Its angular momentum in kg m²/s isRead the answer and worked solution →A force of 20 N acts at a perpendicular distance of 0.3 m from the axis. The torque in N m isRead the answer and worked solution →

Worked practice questions

For a smooth banked road of radius r and banking angle θ, the ideal speed v satisfies

  1. tan θ = rg/v²
  2. sin θ = v²/rg
  3. cos θ = v²/rg
  4. tan θ = v²/rg
Show answer and solution

Correct answer: D. tan θ = v²/rg

The horizontal component of the normal force gives mv²/r while the vertical one balances mg, so tan θ = v²/rg.

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A smooth banked curve has radius 40 m and is designed for 20 m/s. What is the banking angle? (g = 10 m/s²)

  1. 45°
  2. 30°
  3. 60°
  4. 37°
Show answer and solution

Correct answer: A. 45°

tan θ = v²/rg = 400/400 = 1, so θ is 45 degrees.

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On a banked road, the outer edge is raised so that

  1. friction is always zero
  2. friction is needed less
  3. the car weight rises
  4. the road radius shrinks
Show answer and solution

Correct answer: B. friction is needed less

A component of the normal force then helps supply the centripetal force, reducing dependence on friction.

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