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A smooth banked curve has radius 40 m and is designed for 20 m/s. What is the banking angle? (g = 10 m/s²)

A45°
B30°
C60°
D37°
Answer & Solution
Correct answer: A. 45°
tan θ = v²/rg = 400/400 = 1, so θ is 45 degrees.
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