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A solid cylinder rolls from rest down an incline through vertical height h. Its speed at the bottom is

A√(gh)
B√(2gh)
C√(4gh/3)
D√(10gh/7)
Answer & Solution
Correct answer: C. √(4gh/3)
v = √(2gh/(1 + K²/R²)) with K²/R² = 1/2 gives √(4gh/3).
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