alleryStart learning →The total kinetic energy of a rolling body of mass M, speed v, radius R and radius of gyration K is
A½Mv²(1 + K²/R²)
B½Mv²(1 - K²/R²)
C½Mv²(K/R)
DMv²(1 + K/R)
Answer & Solution
Correct answer: A. ½Mv²(1 + K²/R²)
Adding ½Mv² and ½Iω² with I = MK² and ω = v/R gives ½Mv²(1 + K²/R²).
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