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The value of $\sin 30^\circ$ is
A$\dfrac{1}{2}$
B$\dfrac{\sqrt{3}}{2}$
C$\dfrac{1}{\sqrt{2}}$
D1
Answer & Solution
Correct answer: A. $\dfrac{1}{2}$
1. From the standard-angle table, $\sin 30^\circ = \dfrac{1}{2}$.
2. (Correspondingly $\cos 30^\circ = \dfrac{\sqrt3}{2}$.)
3. So $\sin 30^\circ = \dfrac12$.
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch11 'Introduction to Trigonometry', §11.2_
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