alleryStart learning →For an acute angle $A$ in a right triangle, $\sin A$ equals
A$\dfrac{\text{opposite}}{\text{hypotenuse}}$
B$\dfrac{\text{adjacent}}{\text{hypotenuse}}$
C$\dfrac{\text{opposite}}{\text{adjacent}}$
D$\dfrac{\text{hypotenuse}}{\text{opposite}}$
Answer & Solution
Correct answer: A. $\dfrac{\text{opposite}}{\text{hypotenuse}}$
1. $\sin A$ is the ratio of the side opposite A to the hypotenuse.
2. $\sin A = \dfrac{\text{opposite}}{\text{hypotenuse}}$.
3. (cos A uses the adjacent side; tan A = opposite/adjacent.)
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch11 'Introduction to Trigonometry', §11.1_
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