alleryStart learning →Using complementary angles, $\sin(90^\circ - A)$ equals
A$\sin A$
B$\tan A$
C$\cot A$
D$\cos A$
Answer & Solution
Correct answer: D. $\cos A$
1. Angles A and $(90^\circ - A)$ are complementary.
2. $\sin(90^\circ - A) = \cos A$.
3. (Likewise $\cos(90^\circ - A) = \sin A$.)
_Source: Karnataka SSLC (KSEEB) Class 10 Mathematics, Ch11 'Introduction to Trigonometry', §11.3_
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