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Karnataka PUC II Science Electromagnetism — practice questions

Explore 11 free Electromagnetism questions in Karnataka PUC II Science Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Electromagnetism questions and exercises with answers

Showing questions 1–11 of 11.

The force on a charge q moving with velocity v in a magnetic field B (Lorentz magnetic force) isRead the answer and worked solution →The SI unit of magnetic field B isRead the answer and worked solution →A current-carrying straight wire of length l in a magnetic field B experiences force of magnitudeRead the answer and worked solution →Biot–Savart law gives the magnetic field dB due to a current element I dl asRead the answer and worked solution →Ampere's circuital law in integral form statesRead the answer and worked solution →A charged particle moving perpendicular to a uniform magnetic field follows aRead the answer and worked solution →The magnetic field at the centre of a circular loop of radius R carrying current I isRead the answer and worked solution →Inside an ideal infinite solenoid with n turns per unit length carrying current I, the magnetic field isRead the answer and worked solution →The magnetic field at distance r from a long straight wire carrying current I isRead the answer and worked solution →A magnetic field can do work on a moving chargeRead the answer and worked solution →The cyclotron frequency of a particle in a uniform magnetic field B isRead the answer and worked solution →

Worked practice questions

The force on a charge q moving with velocity v in a magnetic field B (Lorentz magnetic force) is

  1. F = q(v × B), vector cross product
  2. F = qE only, independent of B
  3. F = qB / v
  4. F = q(v · B), scalar product
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Correct answer: A. F = q(v × B), vector cross product

Lorentz magnetic force F = q(v × B) — perpendicular to both v and B, magnitude qvB sinθ.

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The SI unit of magnetic field B is

  1. Tesla (T)
  2. Newton (N)
  3. Volt per metre (V/m)
  4. Ampere (A)
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Correct answer: A. Tesla (T)

1 tesla = 1 N / (A · m). Equivalently, 1 T = 1 weber/m² = 10⁴ gauss.

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A current-carrying straight wire of length l in a magnetic field B experiences force of magnitude

  1. F = B / (Il)
  2. F = B²I²l
  3. F = BIl sin θ, where θ is the angle between current direction and B
  4. F = BI / l
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Correct answer: C. F = BIl sin θ, where θ is the angle between current direction and B

F = I l × B; magnitude BIl sinθ. Maximum when current ⟂ field, zero when parallel.

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