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A current-carrying straight wire of length l in a magnetic field B experiences force of magnitude
AF = B / (Il)
BF = B²I²l
CF = BIl sin θ, where θ is the angle between current direction and B
DF = BI / l
Answer & Solution
Correct answer: C. F = BIl sin θ, where θ is the angle between current direction and B
F = I l × B; magnitude BIl sinθ. Maximum when current ⟂ field, zero when parallel.
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