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A charged particle moving perpendicular to a uniform magnetic field follows a
AHelical path of arbitrary pitch
BStraight line accelerated path
CParabolic path
DCircular path of radius r = mv/(qB)
Answer & Solution
Correct answer: D. Circular path of radius r = mv/(qB)
With v ⟂ B, the magnetic force is centripetal: r = mv/(qB). If v has a parallel component too, the path is a helix.
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