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Ampere's circuital law in integral form states
A∮ B · dA = 0
B∮ E · dl = 0
C∮ B · dl = μ₀ I_enc, where I_enc is the current enclosed
D∮ B · dl = μ₀ ε₀
Answer & Solution
Correct answer: C. ∮ B · dl = μ₀ I_enc, where I_enc is the current enclosed
∮ B · dl = μ₀ I_enc. The closed loop integral of B equals μ₀ times the net current threading the loop.
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