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Karnataka PUC I Thermal Properties of Matter & Thermodynamics — practice questions — page 2

Explore 50 free Thermal Properties of Matter & Thermodynamics questions in Karnataka PUC I Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Thermal Properties of Matter & Thermodynamics questions and exercises with answers

Showing questions 31–50 of 50.

In a Carnot cycle, heat absorbed at hot reservoir is 1000 J. Efficiency 25%. Heat rejected at cold reservoir:Read the answer and worked solution →For polytropic process PV^n = constant, n = 0 means:Read the answer and worked solution →In which process is heat capacity infinite for ideal gas?Read the answer and worked solution →NEET · Physics · Thermodynamic ProcessesRead the answer and worked solution →NEET · Chemistry · Exothermic or EndothermicRead the answer and worked solution →NEET · Physics · Heat-Transfer ModesRead the answer and worked solution →NEET · Physics · Calorimetry — Gap FillRead the answer and worked solution →The first law of thermodynamics is a statement of:Read the answer and worked solution →Internal energy of an ideal gas depends only on:Read the answer and worked solution →In an isothermal process for an ideal gas:Read the answer and worked solution →In an adiabatic process:Read the answer and worked solution →For an ideal gas undergoing an isothermal process from V₁ to V₂, the work done by the gas is:Read the answer and worked solution →The relation between Cp and Cv for an ideal gas (per mole) is:Read the answer and worked solution →An ideal gas at temperature T₁ is expanded adiabatically. Its final temperature T₂ is:Read the answer and worked solution →The Carnot engine's efficiency between source temperature T₁ (hot) and sink T₂ (cold) is:Read the answer and worked solution →The second law of thermodynamics can be stated as: no engine can convert into work:Read the answer and worked solution →A Carnot engine operates between 400 K and 300 K. If it absorbs 800 J from the hot reservoir per cycle, the work output per cycle is:Read the answer and worked solution →For an ideal gas the adiabatic equation linking pressure and volume is:Read the answer and worked solution →A refrigerator extracts 600 J from the cold compartment and rejects 800 J to the room. Its coefficient of performance is:Read the answer and worked solution →Which of the following is a reversible process in the thermodynamic sense?Read the answer and worked solution →

Worked practice questions

In a Carnot cycle, heat absorbed at hot reservoir is 1000 J. Efficiency 25%. Heat rejected at cold reservoir:

  1. 1000 J
  2. 500 J
  3. 750 J
  4. 250 J
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Correct answer: C. 750 J

Work done = η × Q_h = 0.25 × 1000 = 250 J. By 1st law (cyclic): Q_h = W + Q_c We have → Q_c = Q_h - W. That is → Q_c = 1000 - 250. So → Q_c = 750 J.

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For polytropic process PV^n = constant, n = 0 means:

  1. Isochoric
  2. Isobaric
  3. Isothermal
  4. Adiabatic
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Correct answer: B. Isobaric

n = 0: PV⁰ = P × 1 = P = constant. So pressure is constant — ISOBARIC. (n = 1 isothermal; n = γ adiabatic; n = ∞ isochoric.)

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In which process is heat capacity infinite for ideal gas?

  1. Adiabatic
  2. Isochoric
  3. Isothermal
  4. Isobaric
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Correct answer: C. Isothermal

Heat capacity C = dQ/dT. In ISOTHERMAL, dT = 0 even with dQ ≠ 0 (heat absorbed but T unchanged). So C → ∞. In adiabatic dQ = 0 regardless of dT, so C = 0.

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