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For an ideal gas undergoing an isothermal process from V₁ to V₂, the work done by the gas is:

An R T ln(V₂/V₁)
Bn R T (V₂ − V₁)
CP (V₂ − V₁)
D(P₂ V₂ − P₁ V₁) / (γ − 1)
Answer & Solution
Correct answer: A. n R T ln(V₂/V₁)
1. At constant T, P V = n R T, so P = n R T / V. 2. W = ∫V₁^V₂ P dV = n R T ∫dV/V = n R T ln(V₂/V₁). 3. (B) is wrong because P is not constant. 4. (C) is the isobaric (constant pressure) work. 5. (D) is the adiabatic work formula. _Source: syllabus Physics Ch 11, §11.7 (isothermal expansion)_
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