For an ideal gas undergoing an isothermal process from V₁ to V₂, the work done by the gas is:
An R T ln(V₂/V₁)
Bn R T (V₂ − V₁)
CP (V₂ − V₁)
D(P₂ V₂ − P₁ V₁) / (γ − 1)
Answer & Solution
Correct answer: A. n R T ln(V₂/V₁)
1. At constant T, P V = n R T, so P = n R T / V.
2. W = ∫V₁^V₂ P dV = n R T ∫dV/V = n R T ln(V₂/V₁).
3. (B) is wrong because P is not constant.
4. (C) is the isobaric (constant pressure) work.
5. (D) is the adiabatic work formula.
_Source: syllabus Physics Ch 11, §11.7 (isothermal expansion)_
Keep practising Thermal Properties of Matter & Thermodynamics
Browse all Thermal Properties of Matter & Thermodynamics questions for AP Intermediate 1st Year, or explore more Physics topics.
Related questions
Isothermal or adiabaticAllowed or forbiddenMatch each statement to its ownerQuick picks on thermodynamicsTrue or false on thermodynamicsClausius arrived at the second law building on the work of Carnot and:A perfect refrigerator is denied by the statement due to:A heat engine takes its working substance around a process that is: