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Karnataka PUC I Classification of Elements and Periodicity in Properties — practice questions — page 2

Explore 48 free Classification of Elements and Periodicity in Properties questions in Karnataka PUC I Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Classification of Elements and Periodicity in Properties questions and exercises with answers

Showing questions 31–48 of 48.

According to Brønsted-Lowry, an acid is a substance that:Read the answer and worked solution →For the dissociation of a weak acid HA, the degree of dissociation α is given (approximately, when α ≪ 1) by:Read the answer and worked solution →Oxidation in modern terms is defined as:Read the answer and worked solution →The oxidation state of sulphur in SO₄²⁻ is:Read the answer and worked solution →The oxidation state of manganese in KMnO₄ is:Read the answer and worked solution →In Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag, the species oxidised is:Read the answer and worked solution →A reducing agent is a substance that:Read the answer and worked solution →Identify the redox reaction:Read the answer and worked solution →The disproportionation of chlorine in cold dilute NaOH (3 Cl₂ + 6 OH⁻ → 5 Cl⁻ + ClO₃⁻ + 3 H₂O is the hot reaction). At cold and dilute conditions, Cl₂ + 2 OH⁻ →:Read the answer and worked solution →In an electrochemical (galvanic) cell, oxidation occurs at the:Read the answer and worked solution →Balance the skeleton equation MnO₄⁻ + Fe²⁺ + H⁺ → Mn²⁺ + Fe³⁺ + H₂O. The coefficient of MnO₄⁻ is:Read the answer and worked solution →Standard hydrogen electrode (SHE) is assigned electrode potential:Read the answer and worked solution →An element shows the SAME oxidation number in all its compounds. Which is it?Read the answer and worked solution →In the half-reaction 2 H₂O → O₂ + 4 H⁺ + 4 e⁻, water acts as:Read the answer and worked solution →The n-factor of KMnO₄ in acidic medium (Mn⁷⁺ → Mn²⁺) is:Read the answer and worked solution →Hydrogen peroxide (H₂O₂) can act both as an oxidising agent AND as a reducing agent because:Read the answer and worked solution →In KO₂ (potassium superoxide), the oxidation state of oxygen is:Read the answer and worked solution →Line up three from one blockRead the answer and worked solution →

Worked practice questions

According to Brønsted-Lowry, an acid is a substance that:

  1. Accepts a proton
  2. Donates a proton
  3. Donates an electron pair
  4. Accepts an electron pair
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Correct answer: B. Donates a proton

1. Brønsted-Lowry: acid donates H⁺ (proton); base accepts H⁺. 2. (A) is the base definition; (C) is the Lewis base; (D) is the Lewis acid. 3. Example: in HCl + H₂O → Cl⁻ + H₃O⁺, HCl is the acid, H₂O is the base. _Source: syllabus Chem Ch 7 §7.10 Brønsted Acids and Bases_

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For the dissociation of a weak acid HA, the degree of dissociation α is given (approximately, when α ≪ 1) by:

  1. α = √(K_a / C)
  2. α = K_a / C
  3. α = √(K_a · C)
  4. α = C / K_a
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Correct answer: A. α = √(K_a / C)

1. HA ⇌ H⁺ + A⁻; K_a ≈ C α² / (1 − α). 2. For α ≪ 1, (1 − α) ≈ 1 and K_a ≈ C α² ⇒ α = √(K_a / C). 3. Hence dilute solutions (small C) have larger α — Ostwald's dilution law. _Source: syllabus Chem Ch 7 §7.10 Ostwald's Dilution Law_

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Oxidation in modern terms is defined as:

  1. Loss of electrons by a species
  2. Gain of electrons by a species
  3. Loss of hydrogen atoms only
  4. Gain of oxygen atoms only
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Correct answer: A. Loss of electrons by a species

1. Modern view: oxidation = loss of electrons; equivalent to an INCREASE in oxidation state. 2. Reduction = gain of electrons (decrease in oxidation state). 3. The old 'loss of H' / 'gain of O' definitions are special cases of the electron-transfer view. _Source: syllabus Chem Ch 8 §8.1 Redox — Electron Transfer_

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