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Karnataka PUC I Chemistry — practice by topic

Browse 564 questions across 11 Chemistry topics. Choose what you want to revise, then open a question to check its answer and worked solution.

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Chemistry topics

Structure of Atom (90)Equilibrium (60)Redox Reactions (58)Chemical Thermodynamics (53)Organic Chemistry: Some Basic Principles and Techniques (53)Hydrocarbons (50)Some Basic Concepts of Chemistry (49)Classification of Elements and Periodicity in Properties (48)Chemical Changes, Reactions & Atmospheric Pollution (47)Chemical Bonding and Molecular Structure (37)The Periodic Table (19)

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According to the octet rule, atoms achieve stability by attaining an outer shell configuration of:Read the answer and worked solution →A heat engine operates with 20% efficiency between two reservoirs. If T_h = 500 K, find T_c (for maximum/Carnot):Read the answer and worked solution →An ideal gas undergoes isothermal expansion at 300 K from V = 1 to V = 2. Heat absorbed (n = 1):Read the answer and worked solution →A diatomic ideal gas at 27°C is compressed adiabatically to ½ its volume. Find final temperature (γ = 7/5):Read the answer and worked solution →

Worked practice questions

According to the octet rule, atoms achieve stability by attaining an outer shell configuration of:

  1. ns² np²
  2. ns² np⁴
  3. ns² np⁶
  4. ns¹ np⁵
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Correct answer: C. ns² np⁶

The octet rule states atoms achieve stability by attaining a noble-gas outer shell of **eight valence electrons (ns² np⁶)**. Helium is the exception with a duplet.

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A heat engine operates with 20% efficiency between two reservoirs. If T_h = 500 K, find T_c (for maximum/Carnot):

  1. 450 K
  2. 300 K
  3. 400 K
  4. 100 K
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Correct answer: C. 400 K

We have η = 1 - T_c/T_h → 0.20. That is η = 1 - T_c/500 → T_c/500. That is η = 0.80 → T_c. So η = 400 K.

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An ideal gas undergoes isothermal expansion at 300 K from V = 1 to V = 2. Heat absorbed (n = 1):

  1. R × 300 × ln(1/2)
  2. R × 300
  3. R × 300 × ln 2
  4. R × 600
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Correct answer: C. R × 300 × ln 2

In isothermal expansion at T, Q = W = nRT ln(Vf/Vi) = 1 × R × 300 × ln(2/1) = 300R ln 2 ≈ 208R J.

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