The oxidation state of manganese in KMnO₄ is:
A+2
B+4
C+6
D+7
Answer & Solution
Correct answer: D. +7
1. K is +1; each O is −2 (four of them = −8); compound is neutral.
2. (+1) + x + 4(−2) = 0 ⇒ x = +7.
3. Mn(+7) is the highest oxidation state — strong oxidising agent.
_Source: NCERT Class 11 Chem Ch 8 §8.3 Oxidation Numbers_
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