The n-factor of KMnO₄ in acidic medium (Mn⁷⁺ → Mn²⁺) is:
A1
B3
C5
D7
Answer & Solution
Correct answer: C. 5
1. n-factor = change in oxidation state per molecule.
2. Mn: +7 → +2, change = 5.
3. So n-factor of KMnO₄ in acidic medium = 5.
4. (In neutral / weakly basic medium, Mn⁷⁺ → Mn⁴⁺, n = 3; in strong base, → Mn⁶⁺, n = 1.)
_Source: syllabus Chem Ch 8 §8.3 Equivalent Concept (extension)_
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