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JEECUP (UP Polytechnic) Wave Optics — practice questions — page 3

Explore 75 free Wave Optics questions in JEECUP (UP Polytechnic) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Wave Optics questions and exercises with answers

Showing questions 61–75 of 75.

Intensity at point in YDSE with phase difference φ between two waves of equal amplitude:Read the answer and worked solution →For single-slit diffraction of width a, angular position of m-th minimum:Read the answer and worked solution →Resolving power of diffraction grating with N lines:Read the answer and worked solution →Width of central maximum in single-slit diffraction:Read the answer and worked solution →Light from a sodium lamp (λ = 590 nm) falls on YDSE with d = 0.5 mm, screen D = 1 m. Fringe width:Read the answer and worked solution →Two slits separated by d emit light of wavelength λ. Angular separation of fringes:Read the answer and worked solution →Resolving power of telescope is given by Rayleigh criterion:Read the answer and worked solution →NEET · Physics · Interference or DiffractionRead the answer and worked solution →Which medium has the higher refractive index?Read the answer and worked solution →Wave optics bingoRead the answer and worked solution →Match the effect to its setupRead the answer and worked solution →Interference, diffraction or both?Read the answer and worked solution →Polarisation: true or false?Read the answer and worked solution →Reflection or refraction?Read the answer and worked solution →True or false: opticsRead the answer and worked solution →

Worked practice questions

Intensity at point in YDSE with phase difference φ between two waves of equal amplitude:

  1. I_max
  2. I × sin φ
  3. I = 4 I₀ cos²(φ/2)
  4. I_max + I_min
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Correct answer: C. I = 4 I₀ cos²(φ/2)

**With two equal-amplitude waves:** I = 4 I₀ cos²(φ/2). At φ = 0 (constructive): I = 4 I₀. At φ = π (destructive): I = 0. Time-averaged intensity over the pattern is 2 I₀ (energy conservation).

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For single-slit diffraction of width a, angular position of m-th minimum:

  1. sin θ_m = m × 2λ/a
  2. No formula
  3. sin θ_m = (m + 1/2) λ / a
  4. sin θ_m = m λ / a
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Correct answer: D. sin θ_m = m λ / a

**Single-slit minima:** a sin θ = m λ (m = ±1, ±2, ...). Note this is opposite of YDSE (which has bright at m λ) single slit has dark at m λ because of within-slit destructive interference.

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Resolving power of diffraction grating with N lines:

  1. Independent of N
  2. 1
  3. N²
  4. Nm (where m = order of diffraction) — Rayleigh criterion
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Correct answer: D. Nm (where m = order of diffraction) — Rayleigh criterion

R = λ/Δλ = Nm. More lines (or higher order) means finer resolution. Used in spectrometers to separate close spectral lines (e.g., sodium D-line doublet).

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