Start learning →

Width of central maximum in single-slit diffraction:

Aλ/a
B2λD/a (twice the slit-to-first-minimum distance)
CD / λ
Dλ a / D
Answer & Solution
Correct answer: B. 2λD/a (twice the slit-to-first-minimum distance)
**Half-width to first minimum:** y = D × λ/a (small angle). So full central max width = 2 × λD/a. Narrower slit → wider central max (diffraction spreads more for smaller apertures).
Practise this question with Quill — JEE Advanced →

Keep practising Wave Optics

Browse all Wave Optics questions for JEE Advanced, or explore more Physics topics.

Start a Wave Optics lesson →