Light from a sodium lamp (λ = 590 nm) falls on YDSE with d = 0.5 mm, screen D = 1 m. Fringe width:
A11.8 mm
B1.18 mm
C118 mm
D0.59 mm
Answer & Solution
Correct answer: B. 1.18 mm
We have β = λD/d.
That is β = (590 × 10⁻⁹)(1)/(5 × 10⁻⁴).
That is β = 1.18 × 10⁻³ m.
So β = 1.18 mm.
Keep practising Wave Optics
Browse all Wave Optics questions for JEE Advanced, or explore more Physics topics.
Related questions
Polarisation of light is direct experimental evidence that light is a:The resolving power (RP) of a diffraction grating with N slits in the m-th order is:In Young's double-slit experiment, the fringe width β is given by:In Young's experiment, a BRIGHT fringe (constructive interference) requires path differencIn single-slit diffraction, the central maximum is:BREWSTER'S LAW for the polarising angle θ_B relates to the refractive index n as:HUYGENS' PRINCIPLE states that every point on a wavefront acts as a:Light passes from air to glass ($n = 1.5$). Brewster's angle is: