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JEECUP (UP Polytechnic) Mechanical Properties of Solids and Fluids — practice questions — page 2

Explore 35 free Mechanical Properties of Solids and Fluids questions in JEECUP (UP Polytechnic) Physics. Open each question or exercise to read its content, reference answers and available explanation.

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Mechanical Properties of Solids and Fluids questions and exercises with answers

Showing questions 31–35 of 35.

For thin spherical shell of water (radius R, thickness t), volume of water:Read the answer and worked solution →For dynamic surface tension in oil drop slowly forming at tip of pipette, drop falls when:Read the answer and worked solution →Compressibility (1/B) of water at standard conditions:Read the answer and worked solution →Match each property of matterRead the answer and worked solution →Solids topic or fluids topic?Read the answer and worked solution →

Worked practice questions

For thin spherical shell of water (radius R, thickness t), volume of water:

  1. π R²
  2. V = 0
  3. (4/3)π R³
  4. ≈ 4π R² t (for t << R, approximate via differential)
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Correct answer: D. ≈ 4π R² t (for t << R, approximate via differential)

dV/dR = 4πR² (surface area). Thin shell V ≈ 4πR² × t for t << R. Useful in fluid dynamics, atomic structure (shell-by-shell electron density).

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For dynamic surface tension in oil drop slowly forming at tip of pipette, drop falls when:

  1. Drop weight = 1
  2. Drop weight ≥ surface tension force (= γ × circumference)
  3. Random
  4. Always falls
Show answer and solution

Correct answer: B. Drop weight ≥ surface tension force (= γ × circumference)

Drop hangs by surface tension force γ × 2πr until weight exceeds it: mg = γ × 2πr → drop falls. Used in stalagmometer to measure surface tension by counting drops/volume.

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Compressibility (1/B) of water at standard conditions:

  1. 10⁻¹⁸
  2. 1 Pa⁻¹
  3. Cannot determine
  4. About 4.6 × 10⁻¹⁰ Pa⁻¹ (B ≈ 2.2 × 10⁹ Pa)
Show answer and solution

Correct answer: D. About 4.6 × 10⁻¹⁰ Pa⁻¹ (B ≈ 2.2 × 10⁹ Pa)

Water bulk modulus B ≈ 2.2 GPa. Compressibility = 1/B ≈ 4.6 × 10⁻¹⁰ Pa⁻¹. Means 1 atm causes ~5 × 10⁻⁵ volume change. Water is nearly incompressible — hence assumption valid in hydraulics.

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