As per your syllabus, after 2 m of cord unwinds at 25 N pull, the work done by the pull is which?
- 100 J
- 12.5 J
- 25 J
- 50 J
Show answer and solution
Correct answer: D. 50 J
syllabus Ex 6.12(b): W = F × distance = 25 × 2 = 50 J. Equals KE gained (energy conservation).