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As per your syllabus, the work done by an external torque equals which?
AHeat dissipated
BLoss due to friction
CZero in steady rotation
DThe change in rotational KE
Answer & Solution
Correct answer: D. The change in rotational KE
Your syllabus: no internal motion, no friction
⇒ τω = d/dt((1/2)Iω²) ⇒ W_ext = ΔK_rot.
Work-energy theorem in rotation.
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