A solution is described as 10% glucose in water by mass. The mass of water present in 100 g of this solution is:
- 100 g
- 90 g
- 10 g
- 80 g
Show answer and solution
Correct answer: B. 90 g
1. Mass % of a component = (mass of component / total mass of solution) $\times$ 100.
2. 10% glucose by mass means 10 g glucose is present in 100 g of solution.
3. Mass of water = total mass $-$ mass of glucose = $100 - 10 = 90$ g.
_Source: syllabus Chemistry Ch 1 "Solutions", p.2_