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A solution contains 20% of ethylene glycol (C2H6O2, molar mass 62 g/mol) by mass in water. Taking 100 g of solution, the mole fraction of ethylene glycol is:
A0.322
B0.068
C0.200
D0.932
Answer & Solution
Correct answer: B. 0.068
1. In 100 g solution: 20 g glycol and 80 g water.
2. Moles of glycol = $20 / 62 = 0.322$ mol; moles of water = $80 / 18 = 4.444$ mol.
3. $x_{glycol} = 0.322 / (0.322 + 4.444) = 0.322 / 4.766$.
4. $x_{glycol} = 0.068$.
_Source: NCERT Class 12 Chemistry Ch 1 "Solutions", p.3_
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