For a weak acid HA that dissociates into one H+ and one A- ion, if the van't Hoff factor is 1.041, the degree of dissociation x is:

1. For HA dissociating into two ions, total particles per mole = $1 + x$. 2. So $i = 1 + x$. 3. $x = i - 1 = 1.041 - 1.000 = 0.041$. _Source: NCERT Class 12 Chemistry Ch 1 "Solutions", p.25_