For a weak acid HA that dissociates into one H+ and one A- ion, if the van't Hoff factor is 1.041, the degree of dissociation x is:
A0.041
B1.041
C0.520
D0.082
Answer & Solution
Correct answer: A. 0.041
1. For HA dissociating into two ions, total particles per mole = $1 + x$.
2. So $i = 1 + x$.
3. $x = i - 1 = 1.041 - 1.000 = 0.041$.
_Source: NCERT Class 12 Chemistry Ch 1 "Solutions", p.25_
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