For a binary solution of two volatile liquids 1 and 2, Raoult's law gives the partial vapour pressure of component 1 as:
Ap1 = p1^0 x1
Bp1 = p1^0 / x1
Cp1 = x1 / p1^0
Dp1 = p1^0 x2
Answer & Solution
Correct answer: A. p1 = p1^0 x1
1. Raoult's law: the partial vapour pressure of each component is proportional to its mole fraction in solution.
2. For component 1, $p_1 = p_1^0 x_1$, where $p_1^0$ is the vapour pressure of pure component 1.
3. The mole fraction used is that of the same component (x1), not the other component.
_Source: NCERT Class 12 Chemistry Ch 1 "Solutions", p.9_
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