For a hydrogen-like atom of nuclear charge $Z$, the radius of the $n$th Bohr orbit scales as
- $r_n \propto nZ$
- $r_n \propto n^2/Z$
- $r_n \propto Z/n^2$
- $r_n \propto n/Z^2$
Show answer and solution
Correct answer: B. $r_n \propto n^2/Z$
$r_n = (0.529\,Å)\,n^2/Z$.
**So radius grows as $n^2$ but shrinks as $Z$ — explaining why He$^+$ has a smaller $n=1$ orbit than H.**