Reaction of XeF₂ with water:
- Inert
- XeF₂ + 2 H₂O → Xe(OH)₂
- No reaction
- XeF₂ + H₂O → Xe + HF + O₂ (disproportionation/hydrolysis)
Show answer and solution
Correct answer: D. XeF₂ + H₂O → Xe + HF + O₂ (disproportionation/hydrolysis)
XeF₂ slowly hydrolyzes: 2 XeF₂ + 2 H₂O → 2 Xe + 4 HF + O₂.
Xenon fluorides are powerful oxidizers. XeF₄, XeF₆ also exist.
Demonstrates that even 'inert' noble gases form compounds under right conditions.