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Indian Navy Pilot Coordination Compounds — practice questions

Explore 33 free Coordination Compounds questions in Indian Navy Pilot Chemistry. Open each question or exercise to read its content, reference answers and available explanation.

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Coordination Compounds questions and exercises with answers

Showing questions 1–30 of 33.

In octahedral crystal-field splitting, what is the energy of the $e_g$ orbitals **relative to** the $t_{2g}$ orbitals?Read the answer and worked solution →What is the coordination number in [Co(NH3)6]³⁺?Read the answer and worked solution →Crystal Field Theory: in an OCTAHEDRAL field, the d-orbitals split into:Read the answer and worked solution →Cis and trans isomers of [Co(NH3)4Cl2]⁺ are examples of:Read the answer and worked solution →For octahedral d6 with weak-field ligands (high-spin), number of unpaired electrons:Read the answer and worked solution →Number of unpaired electrons in [FeF6]³⁻ (high-spin, F⁻ weak-field):Read the answer and worked solution →EDTA is a:Read the answer and worked solution →Sort each ligand by how many donor atoms it usesRead the answer and worked solution →Match each term to its definitionRead the answer and worked solution →True or false: coordination numberRead the answer and worked solution →Counting the coordination numberRead the answer and worked solution →Match each complex to its shapeRead the answer and worked solution →Sort each complex by its geometryRead the answer and worked solution →Complete the coordination sphere ruleRead the answer and worked solution →True or false: ambidentate ligandsRead the answer and worked solution →Chelate or ambidentate?Read the answer and worked solution →Complete the definition of oxidation numberRead the answer and worked solution →Match each theory to what it explainsRead the answer and worked solution →Tap every failing of Valence Bond TheoryRead the answer and worked solution →True or false: the theories and their limitsRead the answer and worked solution →Complete Werner's postulateRead the answer and worked solution →Synergic bonding in metal carbonylsRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Order the steps: read a formula like K₄[Fe(CN)₆]Read the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Flip and pair: term with meaningRead the answer and worked solution →Tap every statement true of a chelate complexRead the answer and worked solution →Reading the definitions backRead the answer and worked solution →

Worked practice questions

In octahedral crystal-field splitting, what is the energy of the $e_g$ orbitals **relative to** the $t_{2g}$ orbitals?

  1. Equal in energy
  2. Lower by $\Delta_o$
  3. Higher by $\dfrac{3}{5}\Delta_o$ (relative to the average level)
  4. Higher by $\Delta_o$
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Correct answer: D. Higher by $\Delta_o$

**Geometry of the splitting.** In an octahedral field, six ligands approach the metal along the $\pm x$, $\pm y$, $\pm z$ axes. The $e_g$ pair ($d_{z^2}$ and $d_{x^2-y^2}$) points *toward* the ligands and is destabilised the $t_{2g}$ trio ($d_{xy}$, $d_{yz}$, $d_{zx}$) points *between* the ligands and is stabilised. **Energy gap.** The energy *difference* between the two sets is called the **crystal-field splitting energy** $\Delta_o$, with $e_g$ **higher** than $t_{2g}$ by exactly $\Delta_o$. - Option C is correct about the $e_g$ rising by $\frac{3}{5}\Delta_o$ above the **unsplit average**, while $t_{2g}$ drops by $\frac{2}{5}\Delta_o$. The total gap is therefore $\frac{3}{5}\Delta_o + \frac{2}{5}\Delta_o = \Delta_o$ — but the question asks for $e_g$ *relative to $t_{2g}$*, not relative to the average. That's $\Delta_o$, not $\frac{3}{5}\Delta_o$. - Option A reverses the direction (in *tetrahedral* splitting the order flips — $t_{2g}$ rises above $e_g$).

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What is the coordination number in [Co(NH3)6]³⁺?

  1. 3
  2. 4
  3. 5
  4. 6
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Correct answer: D. 6

6 NH3 ligands each contributing 1 N donor atom, so coordination number = 6. Geometry: octahedral.

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Crystal Field Theory: in an OCTAHEDRAL field, the d-orbitals split into:

  1. Five equal orbitals
  2. One group
  3. t2g (lower, 3 orbitals) and eg (higher, 2 orbitals)
  4. Two equal sets
Show answer and solution

Correct answer: C. t2g (lower, 3 orbitals) and eg (higher, 2 orbitals)

**In octahedral CF:** t2g (dxy, dxz, dyz — lower energy, 3 orbitals) and eg (dx²-y², dz² — higher energy, 2 orbitals). The splitting Δ_oct = energy gap. Ligand strength determines Δ size.

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