Determinant of [[1,2,3],[4,5,6],[7,8,9]]:
- 0
- -9
- 9
- 18
Show answer and solution
Correct answer: A. 0
Notice row 2 - row 1 = [3,3,3], row 3 - row 1 = [6,6,6] = 2 × (row 2 - row 1).
Rows are linearly dependent, so det = 0. (Also from cofactor expansion.)