The **Hell–Volhard–Zelinsky (HVZ) reaction** converts a carboxylic acid (with $\alpha$-H) to an $\alpha$-halo acid using
- $NaOBr$
- $Br_2$ with red phosphorus
- $Cl_2$ with $hv$
- $KMnO_4$
Show answer and solution
Correct answer: B. $Br_2$ with red phosphorus
$RCH_2COOH + Br_2 \xrightarrow{red\,P} RCHBrCOOH + HBr$.
Red P generates $PBr_3$ which converts the acid to acyl bromide
the $\alpha$-position then enolises and brominates.