A rectangle is inscribed in a semicircle of radius $R$ with base on the diameter. The **maximum area** is:
- $R^2$ (when the rectangle is a square inscribed)
- $2R^2$
- $R^2/2$
- $\pi R^2/2$
Show answer and solution
Correct answer: A. $R^2$ (when the rectangle is a square inscribed)
Half-width = $x$, height $y = \sqrt{R^2 - x^2}$.
Area $A = 2xy = 2x\sqrt{R^2 - x^2}$.
We have $dA/dx = 2\sqrt{R^2 - x^2} - 2x^2/\sqrt{R^2 - x^2}$.
So $dA/dx = 0$.
⇒ $R^2 = 2x^2$ ⇒ $x = R/\sqrt 2$.
Then $y = R/\sqrt 2$, area = $2 \cdot (R/\sqrt 2)(R/\sqrt 2) = R^2$.